How many number roots does the equation have $3x^2-6x+3=0$ ?

Question

4707 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-12-11T06:52:50

1 unique root

$3x^2 - 6x + 3 = 0$

$=> 3(x^2 - 2x + 1) = 0$

$=> x^2 - 2x + 1 = 0$

$=> (x - 1)^2 = 0$

$=> x = 1$

The equation has 1 unique root

How many number roots does the equation have 3x^2-6x+3=03x^2-6x+3=0?