How do you expand $5 (2 y - 3)$ $5(2y-3)$ ?

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Answer 1 · 2016-12-12T23:35:36

$10 y - 15$ $10y - 15$

To expand this expression you need to distribute the $5$ $5$ across the terms within the parenthesis"

$5 (2 y - 3) \to (5 \cdot 2 y) - (5 \cdot 3) \to 10 y - 15$ $5(2y - 3) -> (5*2y) - (5*3) -> 10y - 15$

How do you expand 5(2y−3)5(2y-3)?