A container with a volume of #5 L# contains a gas with a temperature of #400^o K#. If the temperature of the gas changes to #250^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2016-12-13T08:37:45

The new volume is #=3.125L#

We use Charles' Law

#V_1/T_1=V_2/T_2#

#V_1=5L#

#T_1=400K#

#T_2=250K#

Therefore,

#V_2=V_1/T_1*T_2#

#=5/400*250=3.125L#