How do you evaluate #j(h-absh)# when h=-1, j=5?

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Answer 1 · 2016-12-13T14:47:17

#-10#

Consider this example:

#|-6| =|+6|=+6#

So no matter what number you put in the absolute operation it will always come out positive.

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So we have the expression:

#j(h-|h|)" "->" "5(-1-|-1|)#

#=" "5(-1-+1)#

#=" "5(-1-1)#

#=" "5(-2) = -10#