How do you solve #x^2+2x=0#?

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Answer 1 · 2016-12-14T20:26:25

#x = 0# and #x = -2#

You can factor #x^2 + 2x = 0# as:

#x(x + 2) = 0#

Now, we can solve each term for #0#:

#x = 0# - no other work needed,

and

#x + 2 = 0#

#x + 2 -2 = 0 - 2#

#x + 0 = -2#

#x = -2#