How do you solve #9x - 15 = 0#?

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Answer 1 · 2016-12-14T21:05:54

#x = 5/3#

Step 1) Isolate the #x# term on one side of the equation while keeping the equation balanced:

#9x - 15 + 15 = 0 + 15#

#9x - 0 = 15#

#9x = 15#

Step 2) Solve for #x# while keeping the equation balanced"

#(9x)/9 = 15/9#

#(cancel(9)x)/cancel(9) = (3*5)/(3*3)#

#x = (cancel(3)*5)/(cancel(3)*3)#

#x = 5/3#