How do you determine the value of k if the remainder is 3 given $(x^3+4x^2-x+k)div(x-1)$ ?

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Answer 1 · 2016-12-16T01:54:40

$k = -1$ .

the remainder theorem states that if a polynomial $p(x)$ is divided by $x - a$ , then the remainder is given by $p(a)$ .

Here, $a = 1$ and the remainder is $3$ .

So:

$(1)^3 + 4(1)^2 - 1 + k = 3$

$1 + 4 - 1 + k = 3$

$k = -1$

Hopefully this helps!

How do you determine the value of k if the remainder is 3 given (x^3+4x^2-x+k)div(x-1)(x^3+4x^2-x+k)div(x-1)?