How do you solve #2=x+6-2x#?

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Answer 1 · 2016-12-17T14:22:02

#x = 4#

First, isolate the #x# terms on one side of the equation and the constants on the other side of the equation while keeping the equation balanced:

#2 - 6 = x + 6 - 2x - 6#

#-4 = x - 2x + 0#

#-4 = x - 2x#

#-4 = -x#

Now we can multiply each side of the equation by #-1# to solve for #x# and keep the equation balanced:

#-1 xx -4 = -1 xx -x#

#4 = x#