How do you find x and y intercepts of # -6x + 3y = -9#?

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Answer 1 · 2016-12-17T21:41:56

x-intercept is #x = 3/2# or #(3/2, 0).

y-intercept is #y = -3# or (0, -3)

To find the x-intercept, set #y# equal to #0# and solve for #x#:

#-6x + 3*0 = -9#

#-6x + 0 = -9#

#-6x = -9#

#(-6x)/-6 = (-9)/-6#

#(cancel(-6)x)/cancel(-6) = 3/3 * (-3)/-2#

#x = 1 * 3/2#

#x = 3/2# or #(3/2, 0).

To find the y-intercept, set #x# equal to #0# and solve for #y#:

#-6*0 + 3y = -9#

#0 + 3y = -9#

#3y = -9#

#(3y)/3 = (-9)/3#

#(cancel(3)y)/cancel(3) = -3#

#y = -3# or (0, -3)