Question

If `f(x)=x^2-16`, `g(x)=16-x^2`, how do you find `(f-g)(x)`?

Answer 1

`(f- g)(x) = 2(x+ 4)(x - 4)`

Explanation:

Simply subtract the two functions.

`(f- g)(x) = (x^2 - 16 - (16 - x^2))`

`" "= x^2 -16 -16 + x^2`

`" "=x^2 - 32 + x^2`

`" "=2x^2 - 32`

`" "=2(x^2 - 16)`

`" " = 2(x+ 4)(x - 4)`

Hopefully this helps!