Question

Question #54eb5

Answer 1

`3/2x^2+3xy-2x^4=C`

Explanation:

As `(3x+3y)_y '=(3x-8y^3)_x '=3`, the given equation is an exact

differential equation. Now I proceed to integrate. The integral is

`3 int x dx + 3int (ydx+xdy) -8 int y^3 dy`

`=3/2x^2+3int d(xy)-2y^4`

`=>3/2x^2+3xy-2x^4=C`.