Question

Question #ba55e

Answer 1

`LHS=(sin2x)/(secx+1)*(sec2x)/(sec2x+1)`

`=(sin2x)/(secx+1)*(sec2x*cos2x)/(cos2x(sec2x+1))`

`=(2sinxcosx)/(secx+1)*1/(1+cos2x)`

`=(2sinxcosx)/(secx+1)*1/(2cos^2x)`

`=tanx/(secx+1)!=RHS`