Question

Question #34eca

Answer 1

The equation of given straight line is `2x+y=3 or y = -2x+3`

So its slope `m_1=-2`

Hence slope of any straight line perpendicular to it is `m_2=-1/m_1=-(-1/2)=1/2`

If the second straight line passes through `(-7,8)` its equation will be

`y-8=m_2(x-(-7))`

`=>y-8=1/2(x+7)`

`=>y-8=x/2+7/2`

`=>y=x/2+7/2+8`

`=>y=x/2+23/2`