Question

Question #b5be7

Answer 1

The specific heat capacity of the metal is `"0.11 cal·°C"^"-1""g"^"-1"`.

Explanation:

The formula for the heat `q` absorbed by a substance is

`color(blue)(bar(ul(|color(white)(a/a)q = mcΔTcolor(white)(a/a)|)))" "`

where

`m` is the mass of the substance

`c` is the specific heat capacity of the material

`ΔT` is the temperature change

You can rearrange the formula to calculate the specific heat capacity:

`c = q/(mΔT)`

In this problem,

`q = "26.5 cal"`
`m = "50 g"`
`ΔT = "5 °C"`

∴ `c = "26.5 cal"/"50 g × 5 °C" = "0.11 cal·°C"^"-1""g"^"-1"`