How do you find S_n for the geometric series a_1=243, r=-2/3, n=5?
1 Answer
Dec 19, 2016
Explanation:
For the standard geometric series the sum to n terms is.
color(red)(bar(ul(|color(white)(2/2)color(black)(S_n=(a(1-r^n))/(1-r))color(white)(2/2)|)))
"Here " a=a_1=243,r=-2/3" and " n=5
rArrS_5=(243(1-(-2/3)^5))/(1-(-2/3)
=(243(1+32/243))/(1+2/3)=(243+32)/(5/3)=165