How do you find S_n for the geometric series a_1=243, r=-2/3, n=5?

1 Answer
Dec 19, 2016

165

Explanation:

For the standard geometric series the sum to n terms is.

color(red)(bar(ul(|color(white)(2/2)color(black)(S_n=(a(1-r^n))/(1-r))color(white)(2/2)|)))

"Here " a=a_1=243,r=-2/3" and " n=5

rArrS_5=(243(1-(-2/3)^5))/(1-(-2/3)

=(243(1+32/243))/(1+2/3)=(243+32)/(5/3)=165