Question

Question #8011d

Answer 1

`sin(A+B)/sin(A-B) = (a+b)/(a-b)`

By componendo and dividendo

`=>( sin(A+B)+sin(A-B)) /(sin(A+B)-sin(A-B) )=(2a)/(2b)`

`=>(2 sinAcosB) /(2cosAsinB)=a/b`

`=>tanA /tanB=a/b`

`=>atanB =btanA`

Proved