Question

How do you balance `C_4H_8 + O_2 -> CO_2 + H_2O`?

Answer 1

`"Garbage in equals garbage out......."`

Explanation:

The usual rigmarole is (i) balance the carbons, (ii) then the hydrogens, and (iii) then the oxygens.

`C_4H_8 + 6O_2 rarr 4CO_2(g) + 4H_2O(g)`

Can you do same for `"pentane"`, `C_5H_12`? It is a little harder to balance.