Question

Question #1a09d

Answer 1

Given

`secx+tanx=22/7.......[1]`

Again we know

`sec^2x-tan^2x=1.......[2]`

Dividing [2] by [1] we get

`secx-tanx=7/22..........[3]`

Adding [1] and [2] we get

`2secx=22/7+7/22=(484+49)/154=533/154`

`=>secx=533/308`

Subtracting [2] from [1] we get

`2tanx=22/7-7/22=(484-49)/154=435/154`

`=>tanx=435/308`

So `cotx=1/tanx=308/435`

`cscx=secx/tanx=(533/308)/(435/308)=533/435`

Hence
`cscx+cotx=533/435+308/435=841/435`