How do you solve #6\leq \frac { x - 1} { 4}#?

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Answer 1 · 2016-12-25T12:50:48

#x##>=##25#

#6##<=##(x-1)/4#

or, #6**4##<=##(x-1)/4*4rarr#Multiply both sides by 4.

or, #24##<=##x-1#

or, #24+1##<=##xcancel(-1)+cancel(1)#

or, #25##<=##x#

or, #x##>=##25 rarr# 25 is less than equal to #x# which means #x# is greater

than equal to #25#.