Question

If `9/5 L` of a gas at room temperature exerts a pressure of `15 kPa` on its container, what pressure will the gas exert if the container's volume changes to `7/3 L`?

Answer 1

We use the equation `p_1V_1=p_2V_2`

Explanation:

`15xx9/5=p_2xx7/3`

Divide by `7/3` = multiply by `3/7`:

`15xx9/5xx3/7=p_2*cancel(7/3)xxcancel(3/7)`

`->p_2=(3xxcancel5xx9xx3)/(cancel5xx7)=81/7~~11.6kPa`