Question

If `8 L` of a gas at room temperature exerts a pressure of `45 kPa` on its container, what pressure will the gas exert if the container's volume changes to `9 L`?

Answer 1

The gas will exert a pressure of 40 kPa.

Explanation:

We can obtain the final pressure via Boyle's Law:

Let's identify the known and unknown variables:

`color(purple)("Knowns:")`
- Initial Volume
- Final Volume
- Initial Pressure

`color(green)("Unknowns:")`
- Final Pressure

All we have to do is rearrange the equation to solve for the final pressure. We do this by dividing both sides by `V_2` in order to get `P_2` by itself like this:
`P_2=(P_1xxV_1)/V_2`

Now all we do is plug in the values and we're done!

`P_2= (45kPa xx 8cancel"L")/(9\cancel"L")` = `40 kPa`