Question

How do you find the derivative of `y= log_4(x+e^x+e)`?

Answer 1

`=1/ln 4((1+e^x)/(x+e^x+1))`

Explanation:

Use `log_b a= log_c a/log_c b and (ln u)'=(1/u) u'`

So,

`y'=( ln(x+e^x+e)/ln 4)'`

`=(1/(x+e^x+e)(x+e^x+e)')/ln4`

`=1/ln 4((1+e^x)/(x+e^x+1))`