#color(green)("Multiply both sides by 5 to remove the denominator,"#
#cancel5xx(3k-7)/cancel5=16xx5#
5 cancels out on the left side and you're left with #3k-7#. And, when 16 gets multiplied by 5, you get 80 on the right side:
#3k-7 = 80#
#color(magenta)("Add 7 to both sides:")#
#3k-cancel7=80#
#color(white)(aa) +cancel7 color(white)(aa)+7#
The 7's cancel out, so you only have #3k# left. And when you add 80+7 on the right side, you obtain 87:
#3k=87#
#color(red)("Divide both sides by 3 to get k by itself:")#
#(cancel"3"k)/cancel3=87/3#
Now you are just left with #k# on the left side and 29 on the right side.
Thus,
#color(blue)"k=29"#
