How do you solve (3k-7)/5=163k75=16?

1 Answer
Dec 31, 2016

color(blue)"k=29"k=29

Explanation:

color(green)("Multiply both sides by 5 to remove the denominator,"Multiply both sides by 5 to remove the denominator,

cancel5xx(3k-7)/cancel5=16xx5

5 cancels out on the left side and you're left with 3k-7. And, when 16 gets multiplied by 5, you get 80 on the right side:

3k-7 = 80

color(magenta)("Add 7 to both sides:")

3k-cancel7=80
color(white)(aa) +cancel7 color(white)(aa)+7

The 7's cancel out, so you only have 3k left. And when you add 80+7 on the right side, you obtain 87:

3k=87

color(red)("Divide both sides by 3 to get k by itself:")

(cancel"3"k)/cancel3=87/3

Now you are just left with k on the left side and 29 on the right side.

Thus,
color(blue)"k=29"