How do you solve #(1+53)\div 2#?
1 Answer
Explanation:
Use BODMAS (Brackets Orders Division Multiplication Addition And Subtraction. First, add the numbers in the bracket because it's the first, the B, in BODMAS.
#1+53=54#
Then if there's nothing else left in the bracket, move to the outside.
#(54)/2#
Because we only have division left we simply divide
#54/2=27#
Note: if there were other signs besides division, we'd work them out like this:
#(53+1)/2 + 7 * 4#
would be
Bracket first
#53+1=54#
Then division
#54/2=27#
Then multiplication
#7 * 4=28#
This is what it looks like at this stage
#27+28#
Now simply add the two
#27+28=55#