How do you find the solutions of #25c^2+20c=-8c+5c^2#? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer Binayaka C. Jan 1, 2017 Solution: #c=0 or c= -7/5# Explanation: #25c^2 +20c = -8c +5c^2 or 25c^2 +20c +8c -5c^2=0 or 20c^2+28c=0 or 4c(5c+7)=0 or c(5c+7)=0 :. c=0 or 5c+7=0 or c=-7/5# Solution: #c=0 or c= -7/5# [Ans] Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation #81x^2+1=0#? How do you solve #-4x^2+4000x=0#? How do you solve for x in #x^2-6x+4=0#? How do you solve #x^2-6x-16=0# by factoring? How do you solve by factoring and using the principle of zero products #x^2 + 7x + 6 = 0#? How do you solve #x^2=2x#? See all questions in Comparing Methods for Solving Quadratics Impact of this question 1331 views around the world You can reuse this answer Creative Commons License