What is the equation of the line normal to # f(x)=sqrt(1/(x+2) # at # x=-1#?
2 Answers
The equation is
Explanation:
We start by finding the y-coordinate at the given x-point.
We can start by simplifying the function.
We now use the chain rule to differentiate
Let
The slope of the tangent is given by evaluating
The normal line is perpendicular to the tangent, that's to say its slope is the negative reciprocal of that of the tangent.
The equation of the normal line can be found using a point
Hopefully this helps!
Explanation:
To make f real,
At
Its equation is
graph{(ysqrt(x+2)-1)(2x-y+3)=0x^2 [-10, 10, -5, 5]}