Question

How do you find the domain of `p(x)=x^2+4`?

Answer 1

There are no restrictions in the argument of the function, so the domain is `x in(-ooto+oo)`

Explanation:

The range is another story. Since `x^2>=0`:
`p(x) in[4to+oo)`
(the square bracket meaning "inclusive")
graph{x^2+4 [-16.28, 15.76, -2.5, 13.52]}