How do you use the chain rule to differentiate #y=tan^4x#? Calculus Basic Differentiation Rules Chain Rule 1 Answer bp Jan 3, 2017 #4tan^3 x sec^2 x # Explanation: let tan x = t, so that #tan^4 x = t^4# Thus #d/dx tan^4 x= d/dt t^4 dt/dx# #4t^3 d/dx tan x# =#4tan^3 x sec^2 x # Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 3162 views around the world You can reuse this answer Creative Commons License