First, rewrite this problem as:
#(color(red)(5)/color(green)(16))/(color(blue)(3)/color(orange)(10))#
Now, use this rule for dividing equations:
#(color(red)(a)/color(green)(b))/(color(blue)(c)/color(orange)(d)) = (color(red)(a) xx color(orange)(d))/(color(green)(b) xx color(blue)(c))#
#(color(red)(5)/color(green)(16))/(color(blue)(3)/color(orange)(10)) = (color(red)(5) xx color(orange)(10))/(color(green)(16) xx color(blue)(3)) = 50/48 = (2 xx 25)/(2 xx 24) = (cancel(2) xx 25)/(cancel(2) xx 24) =#
#25/24#
