Question

How do you write `p(x) = |x-1| +4` as a piecewise function?

Answer 1

`p(x)={(x+3,,x>=1),(5-x,,x<1):}`

Explanation:

If `abs(x-1)>=0rarr x>=1`
then `abs(x-1)+4 = (x-1)+4=x+3`

If `abs(x-1) < 0 rarr x < 1`
then `abs(x-1)+4 = (1-x)+4 =5-x`