How do you solve #6(y+1)-5=7#?

1 Answer
Jan 6, 2017

We use the order of BODMAS(Brackets Open Division Multiplication Addition Subtraction) to solve any kind of sum,algerba,eqn etc.
eg like this one. Acc to the priority of BODMAS we do operations(+,-,*,/)

Explanation:

I'm solving it here:

#6(y+1) -5=7#

#6(y+1) = 12#

#6y+ 6 =12#

#6y = 6#

#therefore y= 1#