How do you find the 27th derivative of cosx?

1 Answer
Jan 7, 2017

#(d^27y)/(dx^27) = sinx#

Explanation:

Consider the following pattern.

#d/dx(cosx) = -sinx#

#d/dx(-sinx) = -cosx#

#d/dx(-cosx) = sinx#

#d/dx(sinx) = cosx#

So, after differentiating #cosx# four times, you will return to #cosx#!!

Make a list:

#0. cosx#
#1. -sinx#
#2. -cosx#
#3. sinx#
#4. cosx#

So, whenever you have an nth derivative where #n# is divisible by #4#, the derivative will be equal to #cosx#. The closest multiple of #4# to #27# is #28#. The 28th derivative of #cosx# is #cosx#. Go one up in the list #(3)# to find that the 27th derivative of #cosx# is #sinx#.

Hopefully this helps!