How do you use the point on the line and the slope of the line to find three additional points through which the line passes: Point: (7, -2) Slope:m = 1/2?
1 Answer
Here's how you can do that.
Explanation:
All you need to know here is that the slope of the line contains a set of directions that allow you to start from a point that lies on a given line and find other points that lie on the same line.
So, you know that a given line has a slope of
#m = 1/2#
As you know, the slope of a line is defined as the change in
#m = (Deltay)/(Deltax)#
Now, you know that the point
Similarly, the change in
In this case, you have
#m = 1/2 implies {(Deltay = 1), (Deltax = 2) :}#
So, if you start at
#x_2 = 7 + 2 = 9#
Similarly, if you start at
#y_2 = -2 + 1 = -1#
Therefore, a second point on the given line is
Now here comes the cool part, You can use multiples of the slope to find additional points by starting from the same point
#m = 1/2 = 2/4#
This means that you will get
#{(x_3 = 7 + 4 = 11), (y_3 = -2 + 2 = 0) :} implies (11,0)# is another point that lies on the line
Similarly, you can also have
#m = 1/2 = (-1)/(-2)#
In this case, you're moving
This means that
#{(x_4 = 7 + (-2) = 5), (y_4 = -2 + (-1) = -3) :} implies (5,-3)# is another point that lies on the line
Therefore, you can say that
To double-check the result, use one of the points to write the equation of the line
#(y - y_4) = m * (x - x_4)#
#y - 0 = 1/2 * (x - 11)#
#y = 1/2x - 11/2#
The line looks like this
graph{1/2x - 11/2 [-10, 10, -5, 5]}
As you can see, all the points that we've found lie on the line.