Question

How do you write `4/(x+2)+3/(x-2)` as a single fraction in its simplest form?

Answer 1

The answer is `=(7x-2)/(x^2-4)`

Explanation:

`(a+b)(a-b)=a^2-b^2`

The common denominator is `=(x+2)(x-2)`

`4/(x+2)+3/(x-2)`

`=(4(x-2)+3(x+2))/((x+2)(x-2))`

`=(4x-8+3x+6)/(x^2-4)`

`=(7x-2)/(x^2-4)`