Given #csctheta^circ=sqrt3/2# and #sectheta^circ=sqrt3/3#, how do you find #tantheta#?

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Answer 1 · 2017-01-10T06:46:33

The answer is #=2/3#

By definition,

#csctheta=1/sintheta#

#sectheta=1/costheta#

#tantheta=sintheta/costheta#

#=sectheta/csctheta#

#=(sqrt3/3)/(sqrt3/2)#

#=cancel(sqrt3)/3*2/cancel(sqrt3)#

#=2/3#