Question

How do you evaluate the integral `int lnx/xdx`?

Answer 1

`int lnx/x dx = 1/2(lnx)^2+C`

Explanation:

We have that:

`d/(dx) (lnx) = 1/x`

so:

`int lnx/x dx = int lnx d(lnx) = 1/2(lnx)^2+C`