Question

How do you find the values of x and y given `[(x+y, 3), (y, 6)]=[(0, 2y-x), (y^2, 4-2x)]`?

Answer 1

I got:
`x=-1`
`y=1`

Explanation:

For the two matrices to be equal we need that each element of the first to be equal to the correspondent one of the second, or:
`x+y=0`
`2y-x=3`
`y =y^2`
`4-2x=6`

From the last one:
`2x=4-6`
`2x=-2`
`x=-1`
From the first using `x=-1`:
`-1+y=0`
`y=1`