Question #4eef0
1 Answer
Jan 11, 2017
# 1+sec(sqrt(x)) #
Explanation:
In a define integral where one of the limits is a variable it is poor notation to use the same variable as the variable of integration, so I will write
# int_pi^sqrt(x) \ sec(x)tan(x) \ dx # as# int_pi^sqrt(x) \ sec(t)tan(t) \ dt #
We use the known result
# d/dxsecx = secxtanx #
This gives us (without the need for a substitution):
# int_pi^sqrt(x) \ sec(t)tan(t) \ dt = [sect]_pi^sqrt(x) #
# " " = sec(sqrt(x)) - sec(pi) #
# " " = sec(sqrt(x)) - (-1) #
# " " = 1+sec(sqrt(x)) #