Question

Question #aca6e

Answer 1

pH = 11.7

Explanation:

We know that

`["OH"^"-"] = "0.005 mol/L"`.

Then

`"pOH" = "-"log["OH"^"-"] = "-"log(0.005) = 2.3`

We also know that

`"pH + pOH" = 14.00`

∴ `"pH" = "14.00 - pOH" = "14.00 - 2.3" = 11.7`