Question

What is the inverse of the function `f(x)=19/x^3`?

Answer 1

`f^-1(x)=root3(19/x`

Explanation:

let say `f(x) = y`, then
the inverse function, `x =f^-1(y)`

`f(x)=19/x^3`
`y=19/x^3`
`x^3=19/y`
`x=root3(19/y`

`x =f^-1(y)=root3(19/y`
`f^-1(y)=root3(19/y`, then
`f^-1(x)=root3(19/x`