What is the inverse of the function f(x)=19/x^3f(x)=19x3?

1 Answer
salamat
Jan 12, 2017

f^-1(x)=root3(19/xf−1(x)=3√19x

Explanation:

let say f(x) = yf(x)=y, then
the inverse function, x =f^-1(y)x=f−1(y)

f(x)=19/x^3f(x)=19x3
y=19/x^3y=19x3
x^3=19/yx3=19y
x=root3(19/yx=3√19y

x =f^-1(y)=root3(19/yx=f−1(y)=3√19y
f^-1(y)=root3(19/yf−1(y)=3√19y, then
f^-1(x)=root3(19/xf−1(x)=3√19x

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