How do you find the first five terms given #a_1=3/4#, #a_(n+1)=(n^2+1)/n*a_n#? Precalculus Sequences Infinite Sequences 1 Answer Shwetank Mauria Jan 13, 2017 Sequence is #{3/4,3/2,15/4,25/2,425/8,............}# Explanation: As #a_1=3/4# #a_2=a_(1+1)=(1^2+1)/1*a_1=2*3/4=3/2# #a_3=a_(2+1)=(2^2+1)/2*a_2=5/2*3/2=15/4# #a_4=a_(3+1)=(3^2+1)/3*a_3=10/3*15/4=25/2# #a_5=a_(4+1)=(4^2+1)/4*a_3=17/4*25/2=425/8# and sequence is #{3/4,3/2,15/4,25/2,425/8,............}# Answer link Related questions What is a sequence? How does the Fibonacci sequence relate to Pascal's triangle? What is the Fibonacci sequence? How do I find the #n#th term of the Fibonacci sequence? How do you find the general term for a sequence? How do find the #n#th term in a sequence? What is the golden ratio? How does the golden ratio relate to the Fibonacci sequence? How do you determine if -10,20,-40,80 is an arithmetic or geometric sequence? How do you determine if 15,-5,-25,-45 is an arithmetic or geometric sequence? See all questions in Infinite Sequences Impact of this question 1394 views around the world You can reuse this answer Creative Commons License