Question

Given log4=0.6021, log9=0.9542, and log12=1.-792, how do you find log 4.096?

Answer 1

`log4.096=0.6126`

Explanation:

`log4.096`

= `log4096/1000`

= `log4096-log1000`

and as factors of `4096=2xx2xx2xx2xx2xx2xx2xx2xx2xx2xx2xx2=2^12=4^6`

= `log4^6-3`

= `6log2-3`

= `6xx0.6021-3`

= `3.6126-3`

= `0.6126`

Note: We do not need `log9=0.9542`, and `log12=1.0792`. Further, if you check you will find `log4.096=0.6124`. The difference is due to rounding off.