The gas inside of a container exerts #3 Pa# of pressure and is at a temperature of #480 ^o K#. If the temperature of the gas changes to #220 ^oC# with no change in the container's volume, what is the new pressure of the gas?

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Answer 1 · 2017-01-14T16:31:54

1.9 Pa

We know #P_1/T_1 = P_2/T_2# when volume remains same.

here #P_1 = 3 Pa, T_1 = 480 + 273 = 753 k, P_2 = ?#

and #T_2 = 220 + 273 = 493 k #

Now, #3/753 = P_2/493#

#P_2 = [ 3 * 493 ]/753#

#P_2 = 1.9 Pa#