How do you solve 5/2t-t=3+3/2t?

1 Answer
Jan 14, 2017

See entire solution process below:

Explanation:

First, multiply each side of the equation by color(red)(2) to eliminate the fraction and keep the equation balanced:

color(red)(2)(5/2t - t) = color(red)(2)(3 + 3/2t)

(color(red)(2) xx 5/2t) - (color(red)(2) xx t) = (color(red)(2) xx 3) + (color(red)(2) xx 3/2t)

(cancel(color(red)(2)) xx 5/color(red)(cancel(color(black)(2)))t) - 2t = 6 + (cancel(color(red)(2)) xx 3/color(red)(cancel(color(black)(2)))t)

5t - 2t = 6 + 3t

3t = 6 + 3t

We can now subtract color(red)(3t) from each side of the equation:

3t - color(red)(3t) = 6 + 3t - color(red)(3t)

0 = 6 + 0

0 != 6

Because 0 does not equal 6 we know there is no solution for t for this problem other than the null set or t = {O/}