How do you verify the identity #cot^2y(sec^2y-1)=1#?

Question

12352 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-17T20:38:01

see below

Left Hand Side:

Use identity :#1+tan^2y=sec^2y#

#cot^2y(sec^2y-1)=cot^2ytan^2y#

#=cos y/siny * siny /cos y#

#=cancelcos y/cancelsiny * cancelsiny /cancelcos y#

#=1#

#:.=# Right Hand Side