How do you solve #3/7=(x-2)/6#?

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Answer 1 · 2017-01-18T01:25:40

#x=32/7#

Solve #3/7=(x-2)/6#

Multiply both sides by #6#.

#3/7xx6=x-2#

Simplify.

#(3xx6)/7=x-2#

#18/7=x-2#

Multiply both sides by #7#.

#18=7(x-2)#

Expand.

#18=7x-14#

Add #14# to both sides.

#18+14=7x#

Simplify.

#32=7x#

Divide both sides by #7#.

#32/7=x#

Switch sides.

#x=32/7#