How do you simplify #(2xy^0)/(6x)#? Algebra Exponents and Exponential Functions Exponential Properties Involving Quotients 1 Answer Alan P. Jan 18, 2017 #(2xy^0)/(6x)=1/3# Explanation: #(color(red)2color(blue)xcolor(green)(y^0))/(color(red)6color(blue)x)# #color(white)("XXX")=color(red)(2/6) * color(blue)(x/x) * color(green)(y^0/1# #color(white)("XXX")=color(red)(1/3) * color(blue)(1) * color(green)(1)# #color(white)("XXX")=1/3# Answer link Related questions What is the quotient of powers property? How do you simplify expressions using the quotient rule? What is the power of a quotient property? How do you evaluate the expression #(2^2/3^3)^3#? How do you simplify the expression #\frac{a^5b^4}{a^3b^2}#? How do you simplify #((a^3b^4)/(a^2b))^3# using the exponential properties? How do you simplify #\frac{(3ab)^2(4a^3b^4)^3}{(6a^2b)^4}#? Which exponential property do you use first to simplify #\frac{(2a^2bc^2)(6abc^3)}{4ab^2c}#? How do you simplify #(x^5y^8)/(x^4y^2)#? How do you simplify #[(2^3 *-3^2) / (2^4 * 3^-2)]^2#? See all questions in Exponential Properties Involving Quotients Impact of this question 2051 views around the world You can reuse this answer Creative Commons License