Question

How do you find the limit of `x^2+3x` as `x->-3`?

Answer 1

`lim_(x->-3) x^2+3x = 0`

Explanation:

`f(x) = x^2+3x` is a polynomial and as such is continuous on all of `RR`.

So: `lim_(x->-3) f(x) = f(-3) = 9 -9 = 0`