Question

Given `sin30^circ=1/2` and `tan30^circ=sqrt3/3`, how do you find `cos30^circ`?

Answer 1

The answer is `=sqrt3/2`

Explanation:

We use

`tantheta=sintheta/costheta`

`sin30º=1/2`

`tan30º=sqrt3/3`

`cos30º=(sin30º)/(tan30º)=(1/2)/(sqrt3/3)=(1/2)/(1/sqrt3)=sqrt3/2`