Given ${sin 30}^{\circ} = \frac{1}{2}$ $sin30^circ=1/2$ and ${tan 30}^{\circ} = \frac{\sqrt{3}}{3}$ $tan30^circ=sqrt3/3$ , how do you find ${cos 30}^{\circ}$ $cos30^circ$ ?

Question

4821 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-20T07:15:05

The answer is $= \frac{\sqrt{3}}{2}$ $=sqrt3/2$

We use

$tan θ = \frac{sin θ}{cos θ}$ $tantheta=sintheta/costheta$

$sin30º=1/2$

$tan30º=sqrt3/3$

$cos30º=(sin30º)/(tan30º)=(1/2)/(sqrt3/3)=(1/2)/(1/sqrt3)=sqrt3/2$

Given sin30^circ=1/2sin30∘=12sin30^circ=1/2 and tan30^circ=sqrt3/3tan30∘=√33tan30^circ=sqrt3/3, how do you find cos30^circcos30∘cos30^circ?