A container with a volume of #8 L# contains a gas with a temperature of #270^o C#. If the temperature of the gas changes to #390 ^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2017-01-21T06:51:36

The volume is #=5.75L#

We use Charles' Law

#V_1/T_1=V_2/T_2#

#V_1=8L#

#T_1=270ºC+273=543K#

#T_2=390K#

#V_2=T_2/T_1*V_1#

#=390/543*8=5.75L#